Question
By passing 0.50 ampere current in an aqueous solution 0.5 g of an element (Eq. wt -96.5 ) is liberated. The time of passing current in seconds is(a) 100 s(b) 500 s(c) 1000 s(d) 2000 s
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By passing $0.50$ ampere current in an aqueous solution $0.5 \mathrm{~g}$ of an element (Eq. $\mathrm{wt}=96.5$ ) is liberated. The time of passing current in seconds is (a) $100 \mathrm{~s}$ (b) $500 \mathrm{~s}$ (c) $1000 \mathrm{~s}$ (d) $2000 \mathrm{~s}$
By passing $0.50$ ampere current in an aqueous solution $0.5 \mathrm{~g}$ of an element (Equation wt. $=96.5$ ) is liberated. The time of passing current in seconds is: (a) $100 \mathrm{~s}$ (b) $500 \mathrm{~s}$ (c) $1000 \mathrm{~s}$ (d) $2000 \mathrm{~s}$
When an electric current is passed through acidulated, water $112 \mathrm{~mL}$ of hydrogen gas at NTP collects at the cathode in 965 seconds. The current passes, in ampere is a. $0.1$ b. $0.5$ c. $1.0$ d. $2.0$
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