Question
By taking the slope of the curve in Figure $2.75,$ verify that the acceleration is approximately 3.2 $\mathrm{m} / \mathrm{s}^{2}$ at $t=10 \mathrm{s}$
Step 1
Therefore, acceleration can be calculated as the change in velocity over the change in time. Mathematically, this can be represented as: \[a = \frac{{v_2 - v_1}}{{t_2 - t_1}}\] Show more…
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By taking the slope of the curve in Figure, verify that the acceleration is $3.2 \mathrm{~m} / \mathrm{s}^{2}$ at $t=10 \mathrm{~s}$.
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The acceleration of the object at point $D$ on the curve is (A) $0 \mathrm{~m} / \mathrm{s}^{2}$ (B) $5 \mathrm{~m} / \mathrm{s}^{2}$ (C) $-10 \mathrm{~m} / \mathrm{s}^{2}$ (D) $-20 \mathrm{~m} / \mathrm{s}^{2}$
Using approximate values, calculate the slope of the curve in Figure 2.74 to verify that the velocity at $t=10.0 \mathrm{s}$ is 0.208 $\mathrm{m} / \mathrm{s}$ . Assume all values are known to 3 significant fiqures.
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