By using Kirchhoff's Laws, it can be shown that the currents $I_{1}, I_{2},$ and $I_{3}$ that pass through the three branches of the circuit in the figure satisfy the given linear system. Solve the system to find $I_{1}, I_{2},$ and $I_{3}$ $$\left\{\begin{aligned}
I_{1}+I_{2}-I_{3} &=0 \\
16 I_{1}-8 I_{2} &=4 \\
8 I_{2}+4 I_{3} &=5
\end{aligned}\right.$$