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Calcium $-47$ is a $\beta^{-}$ emitter with a half-life of 4.5 days. If a bone sample contains 2.24 g of this isotope, at what rate will it decay?

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$5.12 \times 10^{16} \mathrm{Bq}$

Physics 103

Chapter 30

Nuclear and High-Energy Physics

Atomic Physics

Nuclear Physics

Particle Physics

Rutgers, The State University of New Jersey

Hope College

University of Winnipeg

McMaster University

Lectures

02:42

Atomic physics is the field of physics that studies atoms as an isolated system of electrons and an atomic nucleus. It is primarily concerned with the arrangement of electrons around the nucleus and the processes by which these arrangements change. The theory of quantum mechanics, a set of mathematical rules that describe the behaviour of matter and its interactions, provides a good model for the description of atomic structure and properties.

02:26

In physics, nuclear physics is the field of physics that studies the constituents and interactions of atomic nuclei. The most commonly known applications of nuclear physics are nuclear power generation and nuclear weapons technology, but the research has provided application in many fields, including those in nuclear medicine and magnetic resonance imaging, ion implantation in materials engineering, and radiocarbon dating in geology and archaeology.

01:15

Calcium- 47 , a beta emitt…

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The half-life of calcium-4…

02:31

01:30

Calcium-47, a beta emitter…

05:27

The half-life of calcium- …

05:22

Calcium-47, used to evalua…

02:02

03:47

The half-life for the radi…

01:59

The half-life of calcium-…

01:22

The half-life of a radioac…

01:24

01:38

A radioactive sample conta…

our question wants us to consider calcium 47. So the nuclear number A is equal to 47 which has 1/2 life t 1/2 of 4.5 days. I converted that in the second, so that's 3.88 times 10 to the fifth seconds were told that we have a massive the isotope of 2.24 grams and wants to know that a K rate also wrote out avocados number as in Not. And it's 6.0 to 3 times 10 to the 23rd and we'll see why we need that. So the date the K rate, the number of Adam's lost delta in while the time is changing delta t so that the rain is delta and over delta T and this is equal to lambda the decay rate, constant times the number of atoms that we have in well, Lambda is equal to 0.693 divided by t 1/2. So we know t 1/2. Of course, 0.693 is just a number. So we replaced Lambda with that value and in the number of atoms that we have is simply the mass of the atom, divided by the nuclear on the nuclear on number, eh? Times of a God rose number and not so we replaced in with him over a times and not so we put all those values into this expression. We find that this is equal to five 0.12 times 10 to the six, and then the unit of decay rate is becquerels or B Q. Making box. Sudden is our solution to the question.

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