We know that the molarity of $\mathrm{KMnO}_{4}$ is 0.000988 M and the volume used is 21.08 mL (or 0.02108 L). The number of moles is given by the product of molarity and volume, so we have:
\[0.000988 \, \text{M} \times 0.02108 \, \text{L} = 0.0000208 \,
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