calcium-sulfate-caso-_4-is-only-soluble-in-water-to-the-extent-of-approximately-205-mathrmg-mathrml-

Name: calcium sulfate caso _4 is only soluble in water to the extent of approximately 205 mathrmg mathrml
Uploaded: 2020-05-28
Duration: 2 min 35 s
Channel: Numerade
Description: Calcium sulfate, CaSO $_{4}$ , is only soluble in water to the extent of approximately 2.05 $\mathrm{g} / \mathrm{L}$ at $25^{\circ}$ C. Calculate $K_{\mathrm{sp}}$ for calcium sulfate at $25^{\circ} \mathrm{C}$ .

Question

Calcium sulfate, CaSO $_{4}$ , is only soluble in water to the extent of approximately 2.05 $\mathrm{g} / \mathrm{L}$ at $25^{\circ}$ C. Calculate $K_{\mathrm{sp}}$ for calcium sulfate at $25^{\circ} \mathrm{C}$ .

Anatole Borisov · Accepted Answer

This is a traditional chaos, people. But this time I have to work backwards and forwards in a way. So we&#x27;re going to write out what we have. We have calcium self, It c s so far being which is a solid. Let me be clear about that dissolving to become calcium two plus in a situation. And that&#x27;s a four to minus. Also a quiz. And so writing on ice table like we usually do for these Caspi problems, these equilibrium problems, we ignore the solid. We&#x27;ll have nothing to start with, plus X and plus X over here and Saudi clever. And we have a certain amount acts, which is the same for the calcium two plus in the soffit to minus. And so, if we write out the mass action expression Casspi that&#x27;s gonna be equals the concentration of calcium two plus times a constellation of sulphate, and so that equals X squared, plugging in accidents. And so rest defined ks piece. So if we could figure out what X is that be fantastic and we actually can just not directly. It&#x27;s given to us in the form that the amount of counts himself if they don&#x27;t dissolve is equal to 2.5 grams per leader. And so what we really want to find is we want to find out how many moles that is, because that&#x27;s also gonna be equal to this value of X amount of moles of calcium. That&#x27;s or sulphate that is dissolving. So how are we gonna go from 2.5 grams per leader of calcium sulfate? Two moles well were divided by the molecular weight, which is gonna be 1 36 Ah, 0.14 It&#x27;s divide that one over grams per mole, and so know that the Graham&#x27;s gonna cancel up. And when you do this, you&#x27;re going to get an answer, which is equal to 0.15 most per leader. That&#x27;s are smaller scalability, and that&#x27;s equal to X. And so you said that even toe accidentally remember that a. K S P is just to go to expert. And so this problem becomes much simpler. Suddenly, ksb just square that number and we&#x27;re gonna get 2.25 on me. I think it should be 2.27 Yep, that&#x27;s correct. 2.27 times 10 to the negative. Fourth. There&#x27;s no units because case peers you know its value in. So this is our final answer

Nicole Powell · Answer

the equation for a saturated solution of calcium sulfate. IHS, see a s 04 followed personally Dissociates too See a too close Agrees plus s +04 to minus Equus. That means our K SP is equal to the concentration of see a two plus times the construction of eso for two months In order to calculate the value of the chaos P we have to start by converting or sally ability here into Mueller Sony ability. But that means we have to go from grams well, the little leaders to nos over leaders, which is just polarity. So we have 0.209 grams of c A and so far in 100 milliliters of solution, let&#x27;s start right in the easy part of converting middle leaders. Two leaders there are 1000 milliliters in one leader. Then, just to make sure we&#x27;re cancelling our units correctly, there are middle leaders on top and middle leaders on bottom and we&#x27;re left with leaders on the bottom, which is what we&#x27;re looking for now. We just have to convert our grams to moles and it will get to that. We need to know the molar mass of CSO four to conjecture a periodic table toe. Look up our Mueller mass of, uh, calcium. So? So for now, we just have to convert our grams two moles in order that we need to know the molar mass of cso four so we can check our periodic table to find the molar mass of calcium, sulfur and oxygen. Thank God. Um, all those together where we&#x27;re adding, um, one times the molar mass of calcium, one times the loss of sulfur and four times in the arrests of oxygen. And then we&#x27;ll get the total molar mass of CSR. For once we do that, we get the value boat 1 36.14 grams per mole betweens for every mole of calcium sulfate. We have 1 36.14 grands of calcium sulfate. Now we can make sure our units canceled. We have grams of calcium sulfate on top, anagrams or so casting. Solve it on the bottom milliliters of solution on the bottom and milliliters of solution on the top, when we&#x27;re left with malls of custom sulfate over leaders of solution, which is what we&#x27;re looking for during this calculation, we get a Moeller Sally Ability 0.15 four. You know, we know that we start with 0.15 for Mueller C A s 04 What that means is that once this amount of CSO for dissociates, we&#x27;re left with 0.154 Moeller, see a two plus and 0.154 Moeller eso for two minutes. This is because in our equation of here you have a 1 to 1 ratio between CS and four and see the too close. Meaning we have the same concentration of CIA two plus as we have CSO four and also a 11 ratio. CIA support s a four to minus. Meaning we have the same amount of s 04 to minus as we do CSO for And now we can plug these values into our KSB expression. And so so Caspi is equal to 0.154 moller Times 0.154 Color. This is equal to 2.36 times 10 to the negative Fourth

Katrina Olenwine · Answer

to calculate this eligibility of strong teams sulphate who must first right this eligibility equilibrium reaction, which is simply the ions that make up the solid strong team and selfie. From there we can write the equation for the Souljah bility equilibrium constant, which is the products divided by the re actives. Only that a Prius solutions are included in the equilibrium constant. So since the reactive strong team salty solid, it is not included in the equation. Therefore, the equation is just the concentration of the strontium ion multiplied by the concentration of the sultan Ill. Now we need to fill in an ice table which stands for initial change in equilibrium. For the equation you&#x27;ve written. We don&#x27;t have to worry about filling in the three parts for the solid because it does not factor into the equilibrium. The initial concentration for both of the IOM is zero. But as the solid dissolves in water, the concentration of both ions increases by the same amount which can be represented by X. Therefore, the equilibrium concentration of both ions is X looking ex into the equilibrium constant equation. For both of the ions, we get k equals X squared since we&#x27;re given the value for chaos P which is 3.44 times 10 to the negative seven we can solve for X we can solve for X by taking the square root. Okay, Carrying out the math, we find that the scalability of strong team sulphate is five point 865 times 10 to the negative four moller.

David Collins · Answer

to determine the scalability, the Mueller Celje bility of silver sulfate. Knowing its case, p value impure water. We need to express the silver concentration and the sulphate concentration in terms of bullets eligibility. So because there are two silvers generated than two s is gonna be the silver concentration will. While s ability will just be sulfate concentration. But then rearrange the equation and solve for the Mueller soy ability. And we get 0.14 in pure water. If we already have a presence of silver 0.1 molar concentration and instead of plugging in S or two s for the silver, concentration will plug in 20.1 Moeller itself and square that and self for the Moeller Saudi ability, we get 0.12 Moeller, then for the last one, we know the sulphate concentration at 10.2 Moeller. So we&#x27;ll plug in point to Mueller for the sulfate concentration instead of s and will still plug in to s for the silver concentration because we don&#x27;t know it and we&#x27;re trying to solve for us rearrangement. Then give this point. There is 039 Moeller for the more Celje bility of silver sulfate in the presence of 0.2 more potassium sulfate

Marissa Turner · Answer

This is question 50 from Chapter 22 we have clashed everywhere would having structures made from barium sulfate. So we have to find the scalability in most per liter when they give us K SP is one point out eight times tense in figure 10. So the case, he is basically a sort ability product, and this product is just the squared version of polarity and where similarity is no always per liter. So we&#x27;re going to do is take the square root of this and this is going to come out to be one point so four time to tend to the negative five most pro years. That&#x27;s the song really expressed in most for leader when I was a same polarity.

Aadit Sharma · Answer

The first step is to calculate the solid ability off CSC toe off or impure water. It is The reaction in equilibrium is represented by the chemical reaction. So the initial and equally broom concentration are also showed by the given table. We can calculate the value off s by using the solar ability constant ke sp as you substituting in the values we have sole ability S s four multiplied pretenders Tobar negative five moles per liter. The next step is to calculate the soul ability in one more the hydrogen positive. Firstly, we have to derive the older reaction as shown in this after writing down the acidic form off obsolete on equilibrium, constant with their formation. Next, if this vulnerability s in acidic solution, we can write down the concentration off all the species. As shown in these table, we can calculate the value off s by using the sword ability constant ksb the scalability turn out to be to multiply 10 days to turn negative three moles per liter. Finally, the ratio off soil ability values in acidic solution on border can be calculated else. If in cedar 0.10 Moore&#x27;s off hydrogen positive divided by soil ability, and we would want them equals. Multiply 10 days to my negative three. Divided by four. Multiply it, then, Mr Bern. Negative five. It turns out to be 50. Hence, in acidic solution. The soil ability is 50 times greedo as compared to water.

Problem

Approximately $1.5 \times 10^{-3} \mathrm{g}$ of …

Problem 64 Medium Difficulty

Calcium sulfate, CaSO $_{4}$ , is only soluble in water to the extent of approximately 2.05 $\mathrm{g} / \mathrm{L}$ at $25^{\circ}$ C. Calculate $K_{\mathrm{sp}}$ for calcium sulfate at $25^{\circ} \mathrm{C}$ .

Answer

$2.25 \times 10^{-4}$

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$2.25 \times 10^{-4}$

Introductory Chemistry

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Jacquelin H.

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Steven S. Zumdahl, Donald J. DeCosteIntroductory Chemistry

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