Calculate $\Delta H$ for the reaction
$$
\mathrm{Zn}(\mathrm{s})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{ZnO}(\mathrm{s}) \quad \Delta H=?
$$
given the equations
$$
\begin{aligned}
\mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{ZnCl}_{2}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{~g}) & \Delta H=-152.4 \mathrm{~kJ} \\
\mathrm{ZnO}(\mathrm{s})+2 \mathrm{HCl}(\mathrm{aq}) \rightarrow \mathrm{ZnCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \\
\Delta H=-90.2 \mathrm{~kJ} \\
2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(\ell) & \Delta H=-571.6 \mathrm{~kJ}
\end{aligned}
$$