00:01
To calculate the delta s of formation, we simply need a chemical reaction that takes the elements that comprise the compound and forms one mole of the compound.
00:11
To do this, we're going to need two moles of aluminum, three halves of a mole of oxygen, so we get three moles of oxygen on the right hand side.
00:21
Then we'll look up the entropy, standard entropy for aluminum oxide, and subtract off two times the standard entropy.
00:32
Of aluminum and three halves times the standard entropy of oxygen.
00:37
Now we get negative 313 .1 joules per kelvin mole.
00:42
For the next one we're producing calcium sulfate with half of a water.
00:51
So that means to balance it, we're going to have four and a half oxygens.
00:58
How do we get four and a half out of two? we multiply it by nine -fourths...