00:01
In this problem, we're asked to find the delta s of the surrounding for two reactions.
00:07
First reaction i've written right here.
00:09
So let's begin.
00:12
So i know that my delta s of the surroundings will equal the negative of delta h divided by t.
00:24
T and t will be 298 kelvin because that is 273 plus 25.
00:41
So my delta h or delta s of my surroundings equal the negative of 221 kilojoules divided by 298 kelvin.
01:04
And that will equal, do this, 2, 2, 2, 1 divided by 2, 98 is 7 .453 kilojoules per k.
01:25
And then since we usually report that in joules, that will equal 7 .45 times 10 to the third kilojoules per kelvin.
01:48
Excuse me, joules per kelvin...