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Numerade Educator



Problem 22 Easy Difficulty

Calculate each of the following:
(a) Mass fraction of $\mathrm{C}$ in cesium acetate
(b) Mass fraction of $\mathrm{O}$ in uranyl sulfate trihydrate (the uranyl ion is $\mathrm{UO}_{2}^{2+} )$


percent $(\mathrm{C})=13,35$ percent
percent $(\mathrm{O})=34,28$ percent


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Video Transcript

we had to file the mask, freshen off carbon gin, sees him as a date. So see, See, massive reformers, CSC three CEO, and, um, you can't find out. Ah, mobile mass from the pure people just at the mother mass off individual atoms together. And I should be able to find that this 191.9 grand for more. So for the muff, fraction is we're looking at the mass off carbons. All further mass off the cesium. Our compound. Um, acid Tate. We've no monk. My 100% removed pipe. 100% were must pretends percentage, but with the 12% we will have the mass freshen. So we have Ah, um cabin. So Haman come into we're having our, um uh I only compound, sir. One and see if you have two coppers were 12 times to over 1 91.9 and then we should be able to find out it's foot. There are 17.1 to 5 as a moth mask. Fashion. Okay, The second month freshen will be looking at them right. Fresh enough. Also, June in geranium catches you go. You were no selfie. Try hydrate again you confounded by the mass off this compound from the pure X able you can just add anything together. So we're looking at the mass fashion off oxygen. So it would be close to the ah, the mast to the mass of oxygen in this Ah ah, like compound. So how many all surgeons in this market. So we have to you over here and every air force were six anywhere free in the water. So we have two plus four. 1st 3 were nine oxygen's. We're going to nine times 16 for it to the mass of oxygen. Ah offered Ah, over or what a mess. So we had nine times extinct, divided by two for 20.7. So we we have 0.3 for three. That's, um, class fresher.