00:01
Hello students in this question we have a given one function f x is equal to x square minus one upon x minus one now we need to find the limit of this function which is given as limit x tends to one f x is equal to limit x tends to one x square minus one divided by x minus one 1.
00:34
Now, what we can do here, we will use quotient rule and apply limit to numerator and denominator both and we'll put the value of x tends to 1, which is x is equal to 1 in numerator and denominator and check answer is finite or not.
00:51
So if we can do here, i am simplifying here.
00:55
Okay, so 1 minus 1 upon 1 minus 1, it will, the answer will be 0 by 0.
01:03
And this.
01:04
Form is called indeterminate form.
01:06
So we have to use another method.
01:09
What we will do here? we will do factorization.
01:13
Factorization.
01:21
So we know that x square minus one can be factorized as first we will write limit x 10 to 1, x minus 1 multiplied with x plus 1 divided by x minus 1.
01:39
So we can cancel out here x minus 1 and x minus 1...