00:01
They want us to calculate the formal charges for the non -hydrogen atoms in each of the polymolecules.
00:05
Now, i'm going to do it slightly differently from how they do it in the book.
00:09
They tell us to use this formula, but i think that formula is kind of cumbersome.
00:15
So what we're going to do instead is do this.
00:22
So we're going to do...
00:24
So formal charge, so fc is going to be the amount of electron.
00:31
We normally have, so normal electrons, then we minus how many we actually have for our electrons.
00:43
And it'll be a little bit, make more sense what i mean by normal and have in a second.
00:48
So let's go ahead and start with a.
00:50
So for this carbon here, let's go ahead and actually draw these two hydrogens out.
01:00
So what i like to do is draw a octet in some sense going around it.
01:06
And so now, since these are covalent bonds, that means each of the bonds is going to be sharing one carbon or one electron with each of those.
01:16
So we have one bond here, one bond here, one pond here, one pond here, and one pond here.
01:22
So this means this carbon here has four electrons, essentially for itself.
01:29
So we can come over here to our chart now.
01:32
And remember, this has one electron, two, three, four, four, five, six, seven, eight, and its neutral state as an atom.
01:42
So we would just compare.
01:43
What we have four? and this carbon over here, well, it should have four as well.
01:50
So the formal charge on this is going to be zero.
01:53
So formal charge is zero for this carbon.
01:59
Now what about this nitrogen here? well, let's do the same thing.
02:03
So we can make another little octet that surrounds it like this.
02:07
So each of the bonds is going to be one electron that it has.
02:14
And so that's going to be four.
02:17
So we come over here and we see that nitrogen normally has five.
02:21
So we would do five.
02:24
So it would be five minus four, which gives us one.
02:28
So the formal charge for that nitrogen there is going to be one.
02:33
And then last will we come over to here.
02:36
And so in our octet.
02:41
Notice that, or maybe i should be calling this octet in our orbitals, i should say, in some sense.
02:50
This is going to have, so the two bonds give us one electron each, and then we just count up the lone pairs.
02:57
So we'd have one, two, three, four, five, six.
03:00
So it has six, but nitrogen, or actually i put this in the opposite order.
03:07
So nitrogen normally has five, but it has six, so that's going to give us negative one.
03:16
So the formal charge for that nitrogen is negative one.
03:19
So i think just doing like this normally is a little bit quicker, as opposed to memorizing some formula.
03:27
So let's go ahead and do this the same for this other one down here.
03:31
So let's draw these hydrogens out.
03:35
So one, two, three...