Calculate, in kPa, the pressure exerted by a column of water...

Calculate, in kPa, the pressure exerted by a column of water that is 10-m tall. Assume the weight density of water to be $10,000 \mathrm{N} / \mathrm{m}^{3},$ and ignore the pressure due to the atmosphere.

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Hydrostatic Pressure

Hydrostatic pressure is the pressure exerted by a fluid at equilibrium due to the gravitational force acting on it. This pressure increases linearly with depth in the fluid, as each layer of fluid contributes to the overall pressure experienced at a given depth. The basic relationship is given by multiplying the fluid’s weight density by the height (or depth) of the fluid column.

Weight Density

Weight density is the gravitational force per unit volume of a fluid. It is typically defined as the product of the fluid’s density and the acceleration due to gravity. In calculations involving pressure in fluids, the weight density simplifies the formula by directly relating the pressure to the height of the fluid column without requiring an intermediate step of computing mass times gravitational acceleration.

Unit Conversion

Unit conversion is the process of converting one unit of measurement to another to ensure consistency in calculations. In the context of pressure calculations, results obtained in units such as pascals (or newtons per square meter) may need to be converted to other units like kilopascals. Proper conversion is essential, especially when the problem statement specifies a particular unit for the answer.

Transcript

Please give Ace some feedback