Question
Calculate Kc for each reaction.a. I2(g) 2 I(g) Kp = 6.26 * 10-22 (at 298 K)b. CH4(g) + H2O(g) CO(g) + 3 H2(g)c. I2(g) + CI2(g) 2 IC1(g) Kp = 81.9 (at 298 K)
Step 1
This is done by subtracting the number of moles of reactants from the number of moles of products. For the first reaction, we have 2 moles of I(g) as products and 1 mole of I2(g) as reactant. So, Δn = 2 - 1 = 1. Show more…
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Calculate Kc for each reaction. a. I2(g) 2 I(g) Kp = 6.26 * 10-22 (at 298 K) b. CH4(g) + H2O(g) CO(g) + 3 H2(g) c. I2(g) + CI2(g) 2 IC1(g) Kp = 81.9 (at 298 K)
Calculate Kc for the following reactions a. I2 (g) = 2 I(g) (Kp = 6,26 x 10-22 à 298 K) b. N2O4 (g) = 2 NO2 (g) (Kc = 5,9 x 10-3 à 298 K)
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