This is an indeterminate form of type $0 \cdot \infty$. To handle this, we can rewrite the expression in the form $\frac{0}{0}$ or $\frac{\infty}{\infty}$ to apply L'Hopital's rule. We can rewrite the expression as $\frac{(\ln |x|)^{2}}{\frac{1}{x}}$.
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