00:02
For this next problem, we need to calculate the galvanic cell potential.
00:09
A galvanic cell potential is always going to be a positive potential.
00:13
The equations that were written in the previous problem, 38, suggested that they were already galvanic cells.
00:20
So what was being reduced should have a higher reduction potential, and what was being oxidized should have a lower reduction potential.
00:28
This is the chemical equation that was provided for part a, in question 38.
00:36
So to calculate cell potential, we simply take the cathode reduction potential minus the anode reduction potential.
00:44
Well, what's the cathode? the cathode is where reduction is occurring.
00:48
If you look at this problem, you'll see that reduction is occurring with the iodate, i -o -3 -1.
00:54
And oxidation, the anode, is occurring with iron 2 -plus.
01:00
Therefore, all we have to do is go to the table of reduct...
