Question
Calculate the average value of $f(x)=x \sec ^2 x$ on the interval $[0, \pi / 4]$.
Step 1
So we have: $$\text{Average value} = \frac{1}{\pi/4 - 0} \int_0^{\pi/4} x \sec^2 x \, dx = \frac{4}{\pi} \int_0^{\pi/4} x \sec^2 x \, dx$$ Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Calculate the average value of $ f(x) = x \sec^2 x $ on the interval $ [0, \frac{\pi}{4}] $.
Techniques of Integration
Integration by Parts
Calculate the average value of $f(x)=x \sec ^{2} x$ on the interval $[0, \pi / 4] .$
Calculate the average value of f(x) = 9x sec2(x) on the interval [0, π/4].
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD