00:01
In this question, we're going to be looking at the standard gibbs enthalpy change, gives energy change, which by definition is given as the standard enthalpy change, minus t, the standard enthalpy change, the standard entropy change.
00:14
So this is the formula that we're going to be applying in all the cases.
00:17
For example, for the first system where we have our, we're going to say the standard gibbs energy change is equal to the standard enthalpy change of negative 95 times 10 to the power 3, and this is in jolts minus the temperature of 298 kelvin multiplied by the standard entropy change of 157 joules per kelvin.
00:39
So if we calculate this, the standard gives energy change is going to be negative for 8 times 10 to the power 4 joules.
00:56
So we can conclude here to say this standard gives energy change is going to be equal to negative.
01:06
4 8 kilojoules.
01:08
If we notice this, this value is less than 0.
01:11
So we can conclude that this reaction is spontaneous.
01:17
It spontaneous at 298 kelvin.
01:21
So we always have to make sure that we are making reference to say it's spontaneous at this particular temperature.
01:28
Because if this temperature is, for example, very low or very large, this temperature can change in such a way that the overall gives energy change is going to be a positive value so we always have to make reference to the temperature to say if we look at the gibbs energy change the standard gibbs energy change at a temperature of 298 it is less than zero so this reaction is spontaneous at 298 kelvin so moving on to the next systems we're going to calculate the gibbs energy change being equal to negative 95 times 10 to the power 3 jols my minus 855 multiplied by negative 157.
02:11
So the standard gives energy change here is going to be equal to 39 kilojoules...