00:04
In this question, we are asked to explain the relative chemical shifts of the protons in the benzene ring of nitrobenzene.
00:14
So, nitrobenzine will look like this.
00:16
It has a benzene ring and a nitro group attached to it.
00:21
Nitro group is a electron withdrawing group.
00:25
Let's just keep that in mind.
00:27
And there will be hydrogens in these corners.
00:36
So let's try to identify which of these.
00:39
Protons are equivalent.
00:42
So these two protons that are in the orthoposition compared to the nitro group are equivalent to each other so we can give them a single label.
00:56
These two hydrogens are in the metaposition compared to the nitro group and they are equivalent to each other and this will be the third type of protons present coming from the paraposition relative to the nitro group.
01:18
So let's just use these terms to get to the answer.
01:24
So the orthometta and para protons have different chemical shifts and the question is asking us to explain why this is the case.
01:35
So this is the case because nitrobenzene has resonance structures due to the inductive effect that molecule can display.
01:48
So this is what a nitrobenzine molecule will look like in its normal state.
01:57
Let me draw that.
02:08
This will be the nitrogen.
02:10
There will be one oxygen with a single bond and an extra electron pair on it.
02:15
And then another oxygen with a double bond.
02:20
And then there will be a plus charge on the nitrogen.
02:25
So this bond over here can break towards this plus charge on the nitrogen because this double bond can break towards the oxygen.
02:42
This will form a resonant structure of nitrobenzine and it will look like this.
02:51
So nitrogen will have double bonds with the carbon in the ring.
03:01
And then there will be two oxygens with single bonds...