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Numerade Educator



Problem 18 Easy Difficulty

Calculate the classical momentum of a proton traveling at 0.990$c,$ neglecting relativistic effects. (b) Repeat the calculation while including relativistic effects. (c) Does it make sense to neglect relativity at such speeds ?


a) $4.96 \times 10^{-19} \mathrm{kg} . \mathrm{m} / \mathrm{s}$
b) $3.52 \times 10^{-18} \mathrm{kg} . \mathrm{m} / \mathrm{s}$
c) No


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Video Transcript

momentum B is equal to M times. We huh? You're doing party. And here, uh, M is 1.67 Multiply by 10 to the power minus 27. And we is, uh, 0.99 zero times the speed of light. See and sees tree multiplied by 10 to the power eight. And therefore momentum B is equal to 4.96 multiplied by tend to the power minus 19 kilogram meter per second party. In Barbie, we find Lead Ristic Momentum for logistic Momenta Musical to M We divided by squared Rudolph one minus we squared, divided by C square. Well, let's plug in the values M is 1.67 multiplied by 10 to the dollar, minus 27 kilogram multiply by, um, we is ah, 0.9 90 times the speed of light divided by ah square root off one minus, uh, zero. Find mine. 90 All square six. Great. Gets canceled with C square and therefore, relax Mystic Momenta Musical to 3.52 Multiply by 10 to the power minus 18 kilogram meters per second kilogram meter for a second. No, let's do part. See? Well the answer is no. If we neglect relied with sticky facts If such speech, that editor will be really great. So the Ansari Sze No. And if we, uh, do not consider if they do not consider reliable stick your facts relaxing mystic effects effects. Uh, it's such speeds. It's such speeds. The editor will be really great ever. We'll be really great. So the answer is no.

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