00:01
We have to calculate the concentration of the ion present.
00:03
We have the moles of calcium nitrate.
00:07
So we'll convert to moles of calcium ion using the formula unit given.
00:14
So you can see there's no subscript on the calcium.
00:16
That means one mole of this componentase one mole of calcium.
00:20
Then divide by the total volume of the solution, so that is 100 milliliters.
00:25
Convert it to a liter so that we can have the answer to the alert.
00:28
To convert to liters, divide by 1 ,000, so move the decimal place, we place this to the left.
00:34
And this is going to be the molarity.
00:37
So for the next ion, we're looking at nitrate.
00:40
There are two of them in one molecule of the calcium nitrate.
00:44
So we'll say that one mole contains two moles of the nitrate.
00:48
Divide by the volume that we did with the last part and we'll get the concentration of the nitrate.
00:54
We find it's twice concentration of the calcium, which makes sense.
00:57
So let's go to b.
00:59
So for b, we're going to do the exact thing.
01:01
Same thing.
01:02
So the subscript on the sodium is two...