00:02
Let's calculate the concentration of all solute species in each of the following acids or bases, and we'll have to apply the 5 % rule to see if the assumptions we make are valid.
00:14
For a, we have a weak acid of 0 .0092 molar hcl.
00:22
We were told that as a weak acid.
00:24
We can look up its k -a value, which is 3 .5 times 10 to the negative 8.
00:34
It's calculate the concentration of all species, first by starting to write bronzed lower equilibrium for weak acid.
00:52
Initial malarity, complete a rice table.
01:04
Now assumption here, we're going to assume that 0 .0092 minus x is approximately equal to 0 .0092.
01:14
And our k -a expression, ka is 3 .5 times 10 of the negative 8.
01:36
Solving for x i get 1 .8 times 10 to the negative 5 let's verify our assumption so assumption here 5 % of 0 .0092 is equal to 4 .6 times 10 to the negative 4 so x which is 1 .8 times 10 to the negative 5 is less than 4 .6 times 10 to the negative 4.
02:32
Therefore, since it is less, according to the 5 % rule, the assumption is valid.
02:42
And now we can report the concentration of all species, the concentration of h -3 -0 plus, it's equal to the concentration of clo -minus.
02:50
And where i table, this was x, which is equal to 1 .8 times 10 to the negative 5 molar.
02:55
And the concentration of hclo is equal to 0 .0092 molar as our assumption is valid.
03:03
For b, we have 0 .0784 molar, c6, h5, and h2, and we're told that it is a weak base for the weak base.
03:25
We'll look up the kb value, which is equal to 4 .6.
03:31
Times 10 to the minus 10.
03:33
Let's calculate the concentration of all species.
03:36
Let's write the equation for the weak base.
03:53
And the similarity is 0 .0784.
03:57
Complete a rice table here.
04:06
Kb expression.
04:23
We know the kb values.
04:24
We're going to assume here.
04:26
I didn't write the assumption here.
04:29
But we will, i'll squeeze it in here.
04:32
We're going to assume that 0 .0784 minus x is approximately equal to 0 .0784.
04:42
We'll include that in our expression here.
04:47
The kb we found out was 4 .6 times 10 to the negative 10 from the appendix.
04:52
It's equal to the x, x.
04:56
And our assumption here is 0 .0784.
05:01
Solving for x here, we find that x is equal to 6 .0 times 10 to the negative 6.
05:09
Let's word this above here.
05:14
Let's look at our assumption here.
05:21
5 % of 0 .0784 is equal to 3 .9 times 10 to the negative 3 .3.
05:31
Therefore, x, which is 6 .0 times 10 to the negative 6, is less than 3 .9 times 10 to the negative 3.
05:41
Therefore the assumption is valid.
05:51
Concentration of c6h5nh3 plus is equal to the concentration of oh -1 -8 -1.
06:00
And there are ice table that's they're both equal to x.
06:02
So these are both equal to 6 .0 times 10 to the negative 6 molar.
06:06
And the molarity of the c6h5 and h2 is equal to 0 .0784 molar.
06:16
There would be the concentration of all species.
06:25
For c, we have weak acid .08810 molar hcn.
06:37
We can look up the ca value for hcn, which is equal to 4 .0 times 10 to the negative 10.
06:49
Bronset -lauri equation for hcn.
07:03
Initial malarity, 0810 minus x, x, x, and x...