Calculate the concentration of all species in a 0.500 M solution of H2 SO3 .

Name: Problem 113, Chapter 16: Chemistry A Molecular Approach
Uploaded: 2020-02-24T00:13:22-08:00
Duration: 9 min
Channel: Ahmed Ali
Description: Calculate the concentration of all species in a 0.500 M solution of H2 SO3 .

step 1 Hello everyone, my name is Ahmad Ali. In this question we have a compound which is H2 SO3. This

Calculate the concentration of all species in a 0.500 M...

Key Concepts

Acid Dissociation Equilibrium

This concept involves understanding how a weak acid partially dissociates in water, establishing an equilibrium between the undissociated acid and its ionized species. The degree of ionization is quantified by the acid dissociation constant (Ka), which is used to calculate the equilibrium concentrations of the hydrogen ion and the conjugate base.

Polyprotic Acid

A polyprotic acid is one that can donate more than one proton (H+) in successive steps. Each step of proton donation has its own distinct equilibrium constant, and calculating the concentrations of the various species in solution requires considering each dissociation step and the interactions between them.

Equilibrium Constant Expression

Equilibrium constant expressions mathematically relate the concentrations of reactants and products at equilibrium. In the context of acid-base chemistry, these expressions are critical for setting up the equations necessary to determine the concentrations of all species formed through the dissociation of an acid in solution.

ICE Table Analysis

The ICE (Initial, Change, Equilibrium) table is a systematic method used to organize information about the initial concentrations of species, the changes that occur as the reaction proceeds, and the resulting equilibrium concentrations. This tool is essential for solving problems involving chemical equilibria, including those for polyprotic acid dissociation.

Transcript

00:01 Hello everyone, my name is ahmad ali.

00:02 In this question we have a compound which is h2 so3.

00:08 This compound is weak diprotic acid that means this acid when we dissolving of water first of all it transfer proton to water to be h so3 negative plus hydrogenium.

00:30 This compound do not totally converted to hso3 which its initial concentration is 0 .5, only small amount which is x depending on the value of k -a -1, which is equal 1 .6 times by timber negative 2, converted to hso3, so x and the x value.

00:57 So now, before complete, these hso3 negative maybe ionized again but till here we must find what is a value of x so now we can write that the k e1 which is equal 1 .6 times by timbauer negative 2 is equal the concentration of hs 03 negative which is x times by the concentration of hydrogen which is also x so x squared dividing by the anionized h2 is also a so it is 0 .5 negative x.

01:35 Here the value of k a is very small, not it's big.

01:42 So we cannot neglect the amount of x comparing to 0 .5.

01:47 So we solve it at the following.

01:50 We will time z by z's by this number to be 1 .6 times by tibower negative 2 times by 0 .5.

01:59 Negative 1 .6 times by 10 .2 x all is equal x squared so we can rearrange a to be at the following x squared plus 1 .6 times by team over negative 2 x negative to 1 .6 times by team power negative 2 times by 0 .5 all this is equal 0 so now we have a equation from the second degree here we suppose this one is called the a we suppose this number is called b by the positive sign and we suppose the number negative 1 .6 times by timbauer negative 2 times by 0 .5 is called the c to find the x value using the equation which is negative plus or negative root of b squared negative for a ac divided by 2a.

03:12 So this is the equation that we use at and also we will get two results.

03:21 We will choose the positive one of them.

03:25 So by positive and the negative you will get two results.

03:28 So we will choose only the value that is a positive.

03:31 Post -10 so we will neglect this so by solving 8 we found the x value is 0 .21819 that's mean the concentration of h2 is 0 .5 negative 2 0 .01 sorry 818 which is equal using the calculator will be 0 .5 negative, sorry, 0 .5 negative 0 .0818 to be 0 .4 -182.

04:25 So 0 .4182 is a concentration of an anionized h2s0 .h2s3, and the concentration of hso3 is 0 .203 is 0 .2082...

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