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Problem 94 chapter 14.
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So it wants to calculate the concentration of aqueous strontium hydroxide solution.
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That's ph of 10 .50.
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So remember, strontium hydroxide will dissociate into strong tm2 plus plus 2 -h -o -minus.
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So based on a stoichiometric ratio, the amount of strontium oxide you have is going to be one -half the amount of hydroxide you have.
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Because for every two hydrox, for every hydrox, for every hydropics, so for every charantium oxide you have, you have two hydroxide.
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So it's going to be a 2 to 1 ratio.
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So we know the ph.
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Do find the concentration of hydroxide in solution? we need to find the p .o .h.
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So p .o .h is going to be 14 minus ph.
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It can be 14.
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That's 100 .5.
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0 .50, which is going to be 3 .50...