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Calculate the concentration of ions in the following saturated solutions: (a) $\left[\mathrm{I}^{-}\right]$ in AgI solution with $\left[\mathrm{Ag}^{+}\right]=9.1 \times 10^{-9} M,(\mathrm{b})\left[\mathrm{Al}^{3+}\right] \operatorname{in} \mathrm{Al}(\mathrm{OH})_{3}$ solu-tion with $\left[\mathrm{OH}^{-}\right]=2.9 \times 10^{-9} \mathrm{M}$

$$\begin{array}{l}{\left[T^{-}\right]=9.12 \cdot 10^{-9} \mathrm{M}} \\{\left[A l^{3+}\right]=7.38 \cdot 10^{-8} \mathrm{M}}\end{array}$$

Chemistry 102

Chapter 16

Acid-Base Equilibria and Solubility Equilibria

Acid-Base Equilibria

Aqueous Equilibria

University of Central Florida

Drexel University

University of Kentucky

Lectures

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

24:14

In chemistry, a buffer is a solution that resists changes in pH. Buffers are used to maintain a stable pH in a solution. Buffers are solutions of a weak acid and its conjugate base or a weak base and its conjugate acid, usually in the form of a salt of the conjugate base or acid. Buffers have the property that a small change in the amount of strong acid or strong base added to them results in a much larger change in pH. The resistance of a buffer solution to pH change is due to the fact that the process of adding acid or base to the solution is slow compared to the rate at which the pH changes. In addition to this buffering action, the inclusion of the conjugate base or acid also slows the process of pH change by the mechanism of the Henderson–Hasselbalch equation. Buffers are most commonly found in aqueous solutions.

01:56

Calculate the concentratio…

02:05

01:13

12:24

02:54

02:45

Perform the following calc…

04:12

Determine the concentratio…

04:44

Hello, sir Today will be looking at different compounds dissolved in solution and will be finding out the concentration off the I other ion given one of the ions. So first, let's take a look at the silver variety. So if we dissolve silver, iding and water, it will become a silver plus I own and and I and I died and I on so the Caspi for this molecule would be equal to silver, the silver plus ion concentration and the idea in minus concentration. So the concentration of iady would be given by the Caspi which in this case is 8.3 times 10 to the negative 17 over the concentration of silver which in this case is given as 9.1 times 10 to the negative nine. You'll see that the concentration of I 18 is 9.1 times 10 to the negative nine polarity. Now take Let's take a look at aluminum hydroxide. So we have We're given the hydroxide ion concentration. So let's take a look at what happens when aluminum hydroxide is dissolved. It is absolves, so we know that it dissolves into hydroxide ions. And there three of, um because if we look, we've got three oxygen's into head regions on the left side. We need three on the right and now we see we only have one aluminum. But we have a negative three charge over here. Sweeten it. A three plus charge to balance that out. And so the Casspi would be the concentration off minimum three plus times hydroxide concentration to third power because there's a three coefficient in front of it. So we want to know the concentration of aluminum three plus and that would be equal to the Caspi, which in this case is 1.8 times 10 to the negative 33. And the hydroxide concentration, which is that in this case, is 2.9 times 10 to the negative nine. And it's to the third power. And so we just do some math and we will see that the concentration of aluminum three plus a seven point for times 10 to the negative eight polarity

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