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Hello everyone.
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In this problem, we're asked to find the angular frequency or the cyclotron frequency of a proton that is moving around in a cyclotron.
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Essentially, what's happening here is that you have a uniform magnetic field b perpendicular to which the proton is moving in a circle.
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And so the proton has a mass of 1 .67 times 10 to minus 27 kilograms.
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The field strength we are given is equal to 5 .20 teslas.
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And we know that the charge of the proton is 1 .60 times 10 minus 19 kuloms.
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So what's happening here is that we have the force acting on the proton is the lawrence force, even by q times v times b, provided that the proton is metering perpendicularly to the demand any field, which i have assumed over here.
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And this is equal to the mass times the eight.
00:53
Acceleration, so the newtonian force that's acting on the proton responsible for the motion.
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But now, since the proton is moving in a circle, we also know that the acceleration is that of the centripetal acceleration, which is v squared divided by r.
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For amorven, no doubt at b is equal to two pi times the radius of the motion, of the circular motion, divided by the period of the motion.
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And so this is just saying that, you know, the proton moves around one circumference, covers a length of one circumference in one period.
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And so 1 over t is just equal to f...