Like

Report

Calculate the de Broglie wavelength of a proton moving at $(\text { a }) 2.00 \times 10^{4} \mathrm{m} / \mathrm{s}$ and ( b ) $2.00 \times 10^{7} \mathrm{m} / \mathrm{s}$

a. 1.99 \times 10^{-11} m

b. 1.98 \times 10^{-14} m

You must be signed in to discuss.

Cornell University

Numerade Educator

University of Washington

University of Sheffield

for this one. We want to get that a broadly wavelength. But proton moving at thes two speeds. So be for a is equal to two times 10 to the fore meters per second. And for B, we want to get this for two times. Son of the seventh. So you want to use the formula for Debra Glee wavelength? It's each over pH over m v. So we calculate that for both of these, um, we get the Lambda or this one. Let's go ahead and play everything in and let's use, um so we want to take H and we want to divide it by, um, Emma's 1.67 times 10 to the minus 27 36 things about pro pine and then read two times 10 through the four. And so with that, we got 1.98 times 10 to the minus 11. And then, um, if here it's ah, tender the three times faster. So this is gonna be tended the three times smaller. So that's gonna be 1.90 times 10 to the minus 14 groups, and I almost forgot units, Physicist

University of Washington