00:01
Okay, we're gonna do 15 -134.
00:05
The integration that we must solve is 1 -3, 1 -2, 1 over 1 plus x plus y, d -y -d -x.
00:20
This is 1 -3 -log 1 -x plus -y, and then 1 -2 -d -x, which is 1 -3 -log -2 -d -x, which is 1 -3 -log -log, 3 plus x minus log of 2 plus x dx.
00:48
Now the general integration log of x plus k dx can be solved by the following.
01:02
The first thing we're going to use is us up.
01:05
We're going to set u equals x plus k.
01:09
And this implies that du is equal to d x.
01:14
So we're going to take that step and this can be rewritten as log of u d u.
01:23
Now we're going to do integration by parts...