Calculate the energy change for the reaction
$$
\begin{array}{ll}
\mathrm{NH}_{4} \mathrm{Cl}(s) \longrightarrow \mathrm{NH}_{3}(g)+\mathrm{HCl}(g) \text { from the following: (9.6) } \\
\mathrm{H}_{2}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{HCl}(g) & \Delta H=-184 \mathrm{~kJ} \\
\mathrm{~N}_{2}(g)+4 \mathrm{H}_{2}(g)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{NH}_{4} \mathrm{Cl}(s) & \Delta H=-631 \mathrm{~kJ} \\
\mathrm{~N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g) & \Delta H=-296 \mathrm{~kJ}
\end{array}
$$