Calculate the energy change for the reaction
$\mathrm{Mg}(s)+\mathrm{N}_{2}(g)+3 \mathrm{O}_{2}(g) \longrightarrow \mathrm{Mg}^{2}\left(\mathrm{NO}_{3}\right)_{2}(s)$ from the following: (9.6)
$$
\begin{array}{ll}
8 \mathrm{Mg}(s)+\mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}(s) \longrightarrow \mathrm{Mg}_{3} \mathrm{~N}_{2}(s)+6 \mathrm{MgO}(s) \\
& \Delta H=-3281 \mathrm{~kJ} \\
\mathrm{Mg}_{3} \mathrm{~N}_{2}(s) \longrightarrow 3 \mathrm{Mg}(s)+\mathrm{N}_{2}(g) & \Delta H=+461 \mathrm{~kJ} \\
2 \mathrm{MgO}(s) \longrightarrow 2 \mathrm{Mg}(s)+\mathrm{O}_{2}(g) & \Delta H=+1204 \mathrm{~kJ}
\end{array}
$$