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Calculate the energy, in electron volts, of a photon whose frequency is (a) $6.20 \times 10^{2} \mathrm{THz},$ (b) 3.10 $\mathrm{GHz}$ , and (c) 46.0 $\mathrm{MHz}$

a. 2.57 \mathrm{cV}

b. 1.28 \times 10^{-5} \mathrm{eV}

c. 1.91 \times 10^{-7} e V

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Rutgers, The State University of New Jersey

Numerade Educator

University of Sheffield

University of Winnipeg

Okay, so with this problem, we have a bunch of different frequencies, and we want to get the energy. And so we're gonna use, um e equals H F H is equal to 6.626 times 10 to the minus 34. Dual second. And then for a the frequency is equal to 6.2 times 10 to the second pair of hertz. So that's gonna be times 10 to the 12 hurts. I'm just gonna write them all down, and I'll plug him in. Ah, and then be 3.2 gigahertz and finally, 46 megahertz. And we're gonna put these on, and then we'll divide by 1.6 times 10 to the minus 19 each time to solve for, um t get in terms of jewels. So I'm gonna go ahead and plug these into a calculator. So for the 1st 1 home, it's gonna be 6.20 times, tend to the total of 14 and then let's divide it out by 1.6 times seven, minus 19. And then we got to point. Um, see how many six things should be used to three sick things. So that's 2.57 jewels or E V and then 3.2 times 10 of the nine. With that, I got 1.33 evey and for the next one I got with 46 times 10 to the sex hurts at 1.90 times, 10 to the minus seven e v. It was kind of pies and double check hopes. I realized I made a small typo. So for two, it's actually 3.1, not three point to someone. We go ahead and fix that 3.1, and with that, it slightly changes my answer. Now it's, um, 1.28 something. Go ahead and write that down. And then for the last one. Oh, is it actually 1.28? Sorry. It's like her. I think about the times 10 to the minus five U U groups. And for C territory six megahertz. And so it's double Check the math on. That s so I stand by my work 1.90 times 10 of minus seven TV. Okay,

University of Washington