00:01
So in this problem, we want to calculate the energy of a photon, which is equal to h, new, and new is the frequency, and h is equal to 6 .626 times 10 to the negative 34th joules seconds.
00:20
And so for letter a, we have 100 .2 megahertz, which we want to convert into 1 .002 .2 .2 .2.
00:31
Times 10 to the 8th hertz and then we simply plug that into this equation so 6 .626 times 10 to the negative 34th times 1 .002 times 10 to the eighth and so that we get the energy of that photon is 6 .639 times 10 to the negative 26th joules and that's the final answer for letter a.
01:07
Moving on to letter b, we have that same formula, except this time we have 1070 kilohertz, which is 1 .070 times 10 to the 6th hertz.
01:22
We plug that into that same equation, so 6 .626 times 10 to the negative 34th, times 1 .070 times 10 to the 6th.
01:37
And that equals 7 .090 times 10 to the negative 28th joules...