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Calculate the energy released in the $\beta^{+}$ decay of $^{22} \mathrm{Na}$ the equation for which is given in the text. The masses of $^{22} \mathrm{Na}$ and $^{22} \mathrm{Ne}$ are 21.994434 and 21.991383 $\mathrm{u}$ respectively.

2.842 $\mathrm{MeV}$

Physics 103

Chapter 31

Radioactivity and Nuclear Physics

Nuclear Physics

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Let's write down. Beat a ballistic acreage in beat up lis uh, decay secret gin. Um, well, we have sodium. And they with the atomic mass off 22 atomic number off 11. And this undergoes beat a plastic A and the resulting nucleus. Is he an atomic number or 10? And atomic mass eyes the same. 22 less, uh, beat up less. And then we have new training. Well, energy released in decay. He's, uh uh We need to find out in their energy. Relation to decay. Let's find a Delta am Delta me cools, uh mm into ah, well, Saudi, um, with Tommy command. So 22 minus. Uh, then, uh, Marcelo book this element and e with atomic mess off 22. Um, so most of sodium in Moscow and me. So delta and musical to moss off M A is 21 point mine mine Double four, 34 minus and muscle. And these 21 0.9 mine Ah, one tree If 31383 And this gives this 0.30 51 Hi Atomic mass units. Well, no. Let's find Opener. She Well, we know that e equals M C square here and mist Tel toe him and then c square and we know they'd want atomic mass unity closed mind 31.5 1,000,000 Electron Walt, divided by C Square and therefore inner. She is a cold too. 0.3051 into mine, 31.5 1,000,000 electron volt 1,000,000,000 Electron won't divided by C Square and we multiply this script and therefore energy. It's a cold too. Two point 2.8 for two 1,000,000 electron Oops!

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