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Calculate the equilibrium concentration of $\mathrm{Cu}^{2+}$ in a solution initially with 0.050$M \mathrm{Cu}^{2+}$ and 1.00 $\mathrm{M} \mathrm{NH}_{3}$
$1.0 \times 10^{-13} \mathrm{M}$
Chemistry 102
Chapter 15
Equilibria of Other Reaction Classes
Chemical Equilibrium
Drexel University
University of Maryland - University College
Lectures
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Equal volumes of $0.12 M \…
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let us assume that corporate composite forms the complex, whose concentration is 0.50 moles on the remaining and next three has concentration off. So maybe write it. So concentration for Coco to positive will be 0.50 more low on the remaining concentration off. And it's three will be equal to one point. Siegel minus fool 0.50 which would be almost equal to zero point in zero morning. Let me represent a reaction. It gives out corporate positive plus four Image. Three. We already have the association constant on dhe. Let X b the value of corporate positive in this reaction. So substituting, although, but listen to the formula we have one going toe went to play 10 days to power. 12 equals zero point Tzeitel 50 minus X, divided by sealer 0.80 Plus what excuse to bow before on X solving for X turn out to be 0.50 to buy t play. You don't want it zero days toe before on one going to 10 days to poetry. The equilibrium concentration for corporate positive. I turn out to be 1.0. My depression is to plant negative 30
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