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Calculate the equilibrium concentration of $\mathrm{Ni}^{2+}$ in a $1.0-M$ solution $\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]\left(\mathrm{NO}_{3}\right)_{2}$
0.014 $\mathrm{M}$
Chemistry 102
Chapter 15
Equilibria of Other Reaction Classes
Chemical Equilibrium
Carleton College
University of Central Florida
Rice University
Drexel University
Lectures
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everyone, This is Ricky and that they were working on Problem 85. We're gonna be calculating the equilibrium concentration of nickel to when a one Miller solution of an i n h 3632 and I was inartful. All right, so here is thieves formation of our complex I own. And it has a k off equal to one point. Eat I just into the So let's write our kf expression. I'm black siren on top. And this is a minus two. Not to the power of the negative second, but just the charge. So I couldn't do this. Mixtures of the brackets, the signified concentration we have to react in some bottom where N H three actually is to six. All right. And so so we got is, um, we we can say that the concentrations of Nicholas X and actually would be six x and and I n h 36 would be one Moeller minus X just thinking in terms of our I staple. So it's right out our expressions 1.8 times 10 to the eighth is equal to one point more, which was given to us then questions done x six X because of moment ratios with six, we can assume X is negligible to make our lives easier. And so now when we solve for X, which is also equal to the equilibrium concentration Nicole, we get point 014 molder. So I hope this video is helpful. I'll see when the
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