00:03
Let's calculate the equilibrium concentration of all the unionized acids and ions in a solution that is 0 .134 molar hn .o2 and 0 .120 molar hbro.
00:20
Let's look at these two weak acids.
00:30
And you can write their ionization that occurs in equilibrium.
00:41
And for hno2, the ka is equal to 4 .5 times 10 to the negative 4.
00:48
And for hbro, the ka here would be equal to 2 .0 times 10 to the negative 9.
01:09
Comparing these two here, the ka for hno2 is greater than the ka for hbro.
01:22
Therefore, the first, the hno2 equilibrium will dominate.
01:44
So we're going to start with this one, hno2 at h2o, and so we'll h3o plus, n02 minus.
02:01
Set up a nice table, initial molarity.
02:09
Change equilibrium for their k -a expression.
02:24
K -a is 4 .5 times 10 to the negative 4.
02:28
Substitute our values in.
02:36
We do get a quadratic here.
02:39
Solving the quadratic for x will give me 0 .0075.
02:53
Therefore, the molarity of the h3l plus is .0075 molar.
02:59
Molarity of the no2 minus 0 .05 molar and the molarity of the hno2 will subtract 0 .134 minus 0 .075 and this works out to 0 .127 molar...