Problem

Calculate the equilibrium constant at the tempera…

06:00

Problem 42 Medium Difficulty

Calculate the equilibrium constant at $25^{\circ} \mathrm{C}$ for each of the following reactions from the value of $\Delta G^{\circ}$ given.
(a) $\mathrm{I}_{2}(s)+\mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{ICl}(g) \quad \Delta G^{\circ}=-10.88 \mathrm{kJ}$
(b) $\mathrm{H}_{2}(g)+\mathrm{I}_{2}(s) \rightarrow 2 \mathrm{HI}(g) \quad \Delta G^{\circ}=3.4 \mathrm{kJ}$
(c) $\mathrm{CS}_{2}(g)+3 \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{CCl}_{4}(g)+\mathrm{S}_{2} \mathrm{Cl}_{2}(g) \quad \Delta G^{\circ}=-39 \mathrm{kJ}$
(d) $2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(g) \quad \Delta G^{\circ}=-141.82 \mathrm{kJ}$
(e) $\mathrm{CS}_{2}(g) \rightarrow \mathrm{CS}_{2}(l) \qquad \Delta G^{\circ}=-1.88 \mathrm{kJ}$

Answer

$K=80.57$
$K=0.25$
$K=6.81 \cdot 10^{6}$
$K=7.03 \cdot 10^{24}$
$K=2.13$

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Jewel J.

March 8, 2021

Determine the standard free energy change, ?Gf°, for the formation of S2? (aq) given that the ?Gf° for Ag+ (aq) and Ag2S(s) are 77.1 kJ/mole and ?39.5 kJ/mole respectively, and the solubility product for Ag2S(s) is 8 ×× 10?51

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Video Transcript

So this question asked us to calculate the equilibrium constant. And so we're gonna actually have to derive a formal from that for that, for something with body wouldn't give it well, this formula. And so we're basically just going to go through 100 steps to solve for Katie Que In order to get a formula, we're gonna take a lot of cake. You, and then are going to take anti law, which usually means taking it. Raising it. Um, Toby 10 to the power off. Negative Delta, gee, divided by 2.303 times our teeth here we know T is at 2 98 Kelvin, or room temperature. That's 25 degrees Celsius. And R is this constant of 8.314 joules per mole for Kevin. So again, it's pretty much just plugging chug because they give you all the information we know are we know T. And the question for each part gives us this Dalton She thought so. First for parking. The Delta G standard off negative 10,880. Jules, we're going to get a equilibrium constant of 80.57 movie on Same thing Delta G standard e equals 3400. Put it into the equation at the beginning. And you're any at 0.25 Equilibrium, constant here with ability. Stared equal to negative 3 9000 We're gonna get 6.81 times 10 to the sixth. Has a good room. Constant. Um, parte de delta G stare is negative. 14,001 are sorry. Negative. 141,820 jewels. Put that into the formula at the beginning of this video unit. Get seven. Court, go through tough times. 10 the 24 and last, but not least with Nick with adult G standard of negative. I wouldn't have any 100 individuals you're going to get Get the red 10 very at 2.13 as your equilibrium constant. And because he's equilibrium, constant, they're not gonna have any units associated with, um so just leave it that way back. And that's your answer.

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