00:01
The reaction of sulfur dioxide and oxygen gas reacting to forms sulfur trioxide.
00:07
So in order to find the equilibrium constant, which is our kp, we need to use the equation that our standard free energy of reaction is equal to the negative of the universal gas constant times the temperature that this reaction is run at, times the natural log of our equilibrium constant.
00:28
So let's go ahead and do some algebra here because we're solving for.
00:32
R.
00:34
So the first thing that we can do is we can divide both sides by the negative r times t.
00:43
And that will give us that delta g standard, negative delta two standard over r times t is equal to the natural log of, so we can raise both sides to the e to allow this natural log to cancel.
01:07
And we are left with k is equal to e to the negative delta g standard divided by r times t.
01:22
So let's go ahead and plug in some numbers.
01:27
We know that e to the negative.
01:32
And then from the previous problem, we know that our delta g standard of reaction is negative 141.
01:38
0 .8 kilojoules divided by r, which is 0 .00...