00:02
Hey guys, ladies to problem 3.
00:05
In this problem i need to calculate the equilibrium constant for the given reactions.
00:10
We know the relationship between the standard energy change and the equilibrium constant is given by this equation.
00:18
And at equilibrium, the standard free energy change is equal to 0.
00:23
Therefore we can write down the relation between the equilibrium constant and the standard free energy as this one.
00:31
K equilibrium is equal to exponential negative standard energy change divided by rt and the gas constant r is equal to 8 .31 jule kelvin inverse 1 the temperature is given us 25 degrees celsius let's convert it to kelvin scale by adding to 73 so we get 298 kelvin okay now to calculate the first the equilibrium constant for the first reaction which is glucose 6 phosphate is converting to glucose if we look at the chart we will get that this standard free energy change is given as negative 13 .8 kilojoule per mole let's convert it to jule by multiplying by 1 ,000 so we get 1300 800 13 ,800 joule per mole.
01:33
Now we can calculate what is the equilibrium constant, then k equilibrium is equal to exponential negative, negative 13 jule per mole, divided by the gas constant which is 8 .31 jule, mole inverse 1, kelvin inverse 1, multiplied by the temperature 298 kelvin.
02:04
So when we do this calculation, we will get exponential 13 ,00 ,000 divided by 2477 .9...