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Problem 37

(a) What is the mass, in grams, of $2.50 \times 1…

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Problem 36

Calculate the following quantities:
$$
\begin{array}{l}{\text { (a) mass, in grams, of } 1.50 \times 10^{-2} \text { mol CdS }} \\ {\text { (b) number of moles of } \mathrm{NH}_{4} \mathrm{Cl} \text { in } 86.6 \mathrm{g} \text { of this substance }} \\ {\text { (c) number of molecules in } 8.447 \times 10^{-2} \mathrm{mol} \mathrm{C}_{6} \mathrm{H}_{6}} \\ {\text { (d) number of } \mathrm{O} \text { atoms in } 6.25 \times 10^{-3} \mathrm{mol} \mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}}\end{array}
$$

Answer

a) 2.17 $\mathrm{g}$
b) 1.62 $\mathrm{mol}$
c) 5.085$\cdot 10^{22}$ molecules
d) 3.39$\cdot 10^{22} \mathrm{O}$ atoms


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Video Transcript

Okay, So first part of this problem, we have to find out the massing grams off one point five times two notable minus two. Matloff can be himself. Fight. So to do that first you have to know the mass in crumbs off one more Afghan himself. Fine. So one more cadmium sulphide contents one forty four point five crumb. I can't ma'am sulphide. So this is basically ah, some off the moler mass off. Get vehement sell for So if this is the mess in grams of one more of candy himself, I indictments one point five times ten to the bar, minus two more Can may have certified. Will contain one point five times ten to the porn minus two more times. This fellow for on more on forty four point five Crumb barman, give us a value off who point one seven gram. So this is the mass Engram for one print five times to the bar minus to mall of cadmium sulphide. Now we go to ever nest. Burke, here we have the number of malls off and it's for sale. We have to find out in eighty six point six gram off and it's for sale. Second, we have to know what is the mass ofthe one Mullah vanished. Foresail! So one more land is for sale. Contains fifty three point four nine. Groom in that Men's for eighty six point six gram. Most off and it's for sale. Will it be eighty six point six gram over fifty three point four nine? Graham, you didn't give us one point six tomorrow. So it is experiences. Gram of manage for seal is one point six two. Mall often is for sale or the number of Malta vanished for sale in eighty six points is Graham is one point system on. Now we go to our next problem, where we have to find out Number of molecules and a plan full for seven times in four minus two Mole of six, six six. So first you have to know how many molecules who have in one mal o six, six six. So one more season six will contain. Um, they have a greater number of molecules, which is six point zero two times generally port twenty three and this is the number of molecules in one more off every monocle. So if one Matloff CICC six is thiss then eight point four four seven time stand up or minus to maul will contain eight point four four seven times ten to the four minus two time six pond zero toe time Standard About twenty three. Think of this event off five point zero eight five sometimes and about twenty two. So this is the number of molecules and eight one four, four, seven times into the bar minus tomorrow six, six, six. And I go to our last problem where we have to find out a number of oxygen atoms in this small off aluminium nitrous. So first you have to find out number ofthe molecules off aluminum nitrate in this much more. And for the first few have gone on number of Monica. Listen, one more off aluminium right train, So one more aluminium nitrate contains and in six point zero toe times to deliver twenty three molecules, which is they have a good room number. That means this much number of more off aluminum nitrate will contain six one, two, five times ten to the four minus three time was six point zero two. I'm still with the word twenty three molecules, which is equal to a three point seven six times stated over twenty one. Yeah, molecules. Now, this is the number of molecules of aluminium nitrate in thiss number of malls. And since in one molecule of aluminum nitrate, we have three times three nine oxygen atom let mints In this much molecules off aluminium nitrate, we will have this fellow times nine oxygen atom. We shall give us a fellow off three point three nine times ten to the world twenty two No So this is the number of phantoms of oxygen three point three nine times to get about twenty two in six point two five times tentative are minus three mole off aluminium nitrate.

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