00:02
Part a, let's calculate the freezing point elevation, depression and boiling point elevation for 0 .0 .0 molal mg .c .l.
00:15
2.
00:15
So we're given the malality, magnesium chloride when dissolved in water, will yield magnesium 2 plus and 2cl minus.
00:28
There are three ions present, which will be.
00:34
Labeled as lowercase i in our freezing point depression formula delta t f is equal to i the ionization times the constant which will be the freezing point depression constant for water times the malality the degree of ionization is three times the constant for water which is 1 .86 degrees per molal times the molality which is 0 .050.
01:12
Working this out will yield 0 .28 degrees celsius.
01:28
The freezing point of water is 0 degrees celsius minus 0 .28 degrees celsius for a freezing point depression of minus 0 .28 degrees celsius.
01:42
Now let's calculate the boiling point elevation which will be i times the constant for water times the malality three ions constant for water is 0 .512 degrees celsius per mole malality is 0 .050 working this out will yield 0 .077 degrees celsius the boiling point point for water is 100 degrees celsius plus 0 .077 degrees celsius for a boiling point elevation of 100 .077 degrees celsius.
02:36
Part b to this question is also the freezing point depression and boiling point elevation for 0 .050 moll iron chloride...