00:01
For this question, we start with a .05 molar k -oh solution, and we are asked to solve for the hydronium concentration.
00:10
K -o -h is a strong base, so it completely dissociates.
00:14
So the hydroxide concentration will be the k -o -h concentration.
00:18
To get the hydronium concentration, we simply remember that it is equal to kw, which is 1 .0 times 10 to negative 14, divided by the hydroxide concentration, so we get 2 .0 times 10 to the negative 13 molar.
00:36
To get ph, we simply take the negative log of 2 .0 times 10 to the negative 13, and we get 12 .7.
00:48
Then we are asked to write a balanced chemical reaction for k -o -h and sulfuric acid.
00:54
This is a hydroxide -containing compound reacting with an acid.
00:59
It will always produce water and a salt.
01:01
The salt will have its cation coming from the base and anion, from the acid...