00:01
All right, so for this problem, we're given multiple phs, and then we're asked to find their related proton concentrations.
00:10
So, of course, to solve this problem, we have to keep in mind this equation at the top.
00:14
Ph is equal to the negative log of the concentration of protons.
00:20
So how do we solve this? so we know that the ph is going to be equal to the negative log of our proton concentration.
00:30
So we know that if we move this negative sign, negative 7 .4 will equal the log of the proton concentration.
00:41
Now, we can use an anti -log for this, but what i find easier to do is just from the nature of the log, you can get rid of the log by 10 to the power of both sides.
00:53
This will give us 10 to the negative 7 .4 is equal to the concentration of protons.
01:01
That's just the nature of the log.
01:03
That's how logs work because the log 10 automatically.
01:10
So we know for this 10 to the negative 7 .4, the power of negative 7 .4, but i'll give us a proton concentration equal to 3 .98 times 10 to the negative 8 molar...