00:01
Welcome to numerate.
00:02
With this current problem, we are given the displacement function as this is equal to 4t plus 10.
00:14
Now, we are not going to find this using the usual method to find the instantaneous velocity at t equals to 3.
00:25
To verify if we are going towards the current value, let us find what would it would be.
00:32
So d s d t would be nothing but d d t of 4 t plus 10 and as you would learn for constant like it will split twice like this 40 dd t plus dd t of 10.
00:52
Okay and then constant goes out if it is being multiplied so d dd t plus 0 because for constant there is no difference.
01:03
And then 4 into 1.
01:05
So the dsd is 4 always.
01:09
So ds d t will be equals to 4 even if 40 is equals to 3.
01:14
So now our answer is ready but we will take the other approach to come to the same answer and make our understanding better.
01:23
So first we are given the time as 2, 2 .5, 2 .9, 2 .5 2 .99 and 2 .999.
01:43
Now what will be s which is in fit it will be if i plug in the values over here of t...