00:01
So let's take a look at number a first.
00:03
So 100 joules of work is done on the system.
00:06
That means w is 100, positive 100.
00:14
And the gas releases 23 joules of heat.
00:17
Since heat is released from the system, q is negative 23.
00:24
And according to the change of the internal energy equation, delta e equal to q plus w.
00:29
If you add these two together, you get, these 7 joules of energy.
00:39
For the second question, we'll use the equation w equal to p delta v.
00:49
So we have a p value of 1 .9, v value of 5 .5 because how we get the volume is 8 .3 liters minus the 2 .a.
01:05
We have 5 .5.
01:09
And that's our volume.
01:10
Times 1 .9 pressure and we will get 10 .45 latm and if you were to convert that to jewel for every 1latm there is 101 .3 joules so if you just use this value times the 101 .3 you will eventually get 105 .8 .6 joules of energy.
01:50
So the system gains the heat of 350 joules, q equal to positive 350.
01:59
And if we use the first equation, e equal to q plus w, you add 350 plus or 105 .6.
02:09
You will eventually get 1 .408 .6...