Calculate the irreversibility for the process described in Problem 4.154, assuming that heat tra

step 1 So let's talk with the given data. Now we have been given the volume water for ale in the piston

Calculate the irreversibility for the process described in...

Key Concepts

Second Law of Thermodynamics

The second law of thermodynamics states that the total entropy of an isolated system can never decrease over time. This principle underpins the concept of irreversibility by ensuring that real processes always involve some increase in entropy, distinguishing them from idealized reversible processes where entropy remains constant.

Heat Transfer with a Thermal Reservoir

Utilizing a thermal reservoir, such as surroundings at a constant temperature, simplifies the analysis of heat transfer in a process. The constant-temperature assumption allows for straightforward computation of entropy changes associated with heat transfer, making it easier to evaluate the degree of irreversibility present in the process.

Entropy Generation

Entropy generation is the measure of disorder created within a system during a process. It occurs as energy transformations take place in irreversible processes and is a direct indicator of losses incurred due to irreversibility. According to the second law of thermodynamics, any irreversible process will produce a net increase in entropy.

Irreversibility

Irreversibility in thermodynamics refers to the natural tendency of real processes to deviate from an ideal, reversible path. It quantifies the inherent inefficiencies and lost work due to factors such as friction, unrestrained expansion, and heat transfer across finite temperature differences, highlighting that some energy becomes unavailable for doing useful work.

Transcript

00:01 So let's talk with the given data.

00:03 Now we have been given the volume water for ale in the piston cylinder right here in the piston cylinder.

00:13 Right.

00:14 So the first thing that we have been given is the pressure, right, b sub 1, the first initial pressure, right? so that is equal to 300 kilo -pascals and we have been given the pressure or the line, right? so that is equal to 500 kilo -pascals right and then we have been given the second pressure right so that is equal to 400 kilo -pascals right now you can see it has been increased and then we have been given the first temperature the initial temperature that is equal to 290 calvin and then we have been given the ambient temperature right so that is equal to 290 calvin then we have been given the temperature for the line right so that is equal to 290 calvin then we have been given the temperature for the line right so that is equal to 600 kelvin and then we have been given the final temperature right so that is equal to 350 calvins and then we have been given the volumes as well so the initial volume it's equal to point two five meter cube right and the final volume it's equal to one meter cube now what we going to do is that the first step it is to refer to the table a point five right and we can find the air specific heat and gas constant right so the gas constructs equal to 0 .287 kilojoules per kilogram calvin right and then we have the heat capacity right so that is 1 .004 kilojoules per kilogram kelvin right and then we have the specific heat constant, right? so that is equal to 0 .717 kilojoules per kilogram calvin.

02:10 Right.

02:12 Now that we have these values, we are going to calculate the stage one mass by using the ideal gas equate.

02:26 Right so you would get that the stage 1 mass is equal to b1 b sub v1 sorry p sub 1 times v 1 divided by r times d sub 1 we have all the values just plug them in over here and we would get the stage 1 mass that is equal to 0 .9 kilograms right now that we have this we are going to calculate the stage 2 mass, right? so again, it would be m sub 2 and it would be equal to p sub 2 times v sub 2 divided by r times t sub 2.

03:09 Again, just plug in the values.

03:11 We have all the values and we would get the stage 2 mass that is equal to 4 kilogram.

03:16 Now that we have the stage 1 and stage 2 mass, we can calculate the heat transfer.

03:21 Right.

03:22 So i'm going to calculate the heat...

Please give Ace some feedback