00:01
So in this question, it's given to us that radium 226 decays to radon 222 and an alpha particle.
00:22
And we are asked to calculate the kinetic energy of the alpha particle, given that the radium is at rest.
00:33
So first of all, calculating the q value of this reaction.
00:38
So q value would be mass of radium 226 minus minus mass of radon 222 minus mass of helium 4 times c square where c squared is 931 .5 mev per u so this q value comes out to be 4 .8707 mev now the q value can also be written as kinetic energy of products.
01:28
So kinetic energy of radon 222 plus kinetic energy of helium 4 minus kinetic energy of radium 226.
01:47
So this is given to be zero to us.
01:54
So our q value would be kinetic energy of radon plus kinetic energy of helium four.
02:03
Now, let us conserve momentum in this reaction.
02:13
So conserving momentum, initial momentum is zero because radium is at rest...