00:02
Hello there.
00:04
For this problem, they're telling us that acetic acid has an acid dissociation of constant of 1 .8 times 10 to negative 5.
00:16
They want to know what is the ph of a buffer solution, contains 0 .5 of acetic acid and 0 .5 of acetate.
00:26
So how we go about this? we see that for our k, for our ka, that this is how you would normally set it up if we're just solving for this.
00:39
But since we have this, we have the numbers for our ka, our numbers for acetate, and our number for acetic acid.
00:49
We don't have the numbers for hydronium.
00:51
So we're going to solve for hydronium.
00:54
And this is how the chemicals are set up.
00:57
I mean, the equation is set up, so let's begin.
01:00
So we'll pop add the numbers into the equation, and when we calculate it, we end up getting 1 .8 times 10 to negative 5...