00:01
Belongs to the gravitational chapter and according to this question we have to calculate the magnitude of gravitational force fg on the moon due to sun and earth so suppose this is the diagram for this condition okay so this is the diagram in which this is the sun and this is the moon and this is the earth okay so the gravitational force on the moon due to sun will be in this direction and the gravitational force on the moon due to earth will be in this direction.
00:30
These are the distance between earth and moon and sun and earth.
00:34
So, now we can calculate the gravitational force applied by the sun f s.
00:39
This will be equals to g mass of sun, mass of moon, divided by r .s .e minus r small r we can take as per the diagram.
00:51
So rse minus r e m whole square.
00:55
Okay.
00:56
So this will become the distance from here to here.
01:00
So, substituting values, so we will get that force applied by the sun f s, this will be equals to 6 .67 into 10 to the power minus 11.
01:08
This is the value for the g and mass of the sun which is 1 .99 into 10 to the power 30 kg and mass of the moon which is 7 .3 double 4 multiplied by 10 to the power 22 kg divided by distance between sun and earth which is 1 .496 into 10 to the power 11 meter and distance between in earth and moon which is 3 .8 double 4 multiplied by 10 to the power 8 meters.
01:35
So whole is where.
01:36
So from here after solving, we will get that force applied due to the sun on the moon f s equals to minus 4 .381 multiplied by 10 to the power 20 newton into x -capped direction minus x kept direction.
01:50
Suppose this is our x direction and this is the y direction...