00:01
In answering this question, we have to recall that the ph is equal to negative log concentration of the h3 or positive ions.
00:09
Now, what this means is the concentration of the h3 or positive ions is going to put 10 to the power negative ph, which in this case is equal to 3 .5, which is equal to 3 .2 multiplied by 10 to the power negative 4 in units of molarity.
00:25
So what this is telling us right here, this is the concentration of h3 or positive ions that must be supplied by the benzoyic acid in order to produce a solution that is equal to 3 .5, whose ph is equal to 3 .5.
00:42
So what we want to do here is to determine the volume of the benzoy acid rather the mass of the benzoy acid that when dissolved in solution, it will produce a concentration of h.
00:55
3 or positive ions of 3 .2 by 10 to the power negative 4 which corresponds to a ph of 3.
01:02
Now looking at this what we are doing here is we have the benzoic acid that is going to dissolve in solution to produce the benzoyac acetate or rather let's just write this as c6 h5 c.
01:19
That dissolves in solution to produce c6 this will be in h2 or producing c6 h5 c0 negative plus h3o positive.
01:32
So looking at this, we've got an initial concentration that we do not know.
01:37
And because before the actual ionization takes place, we won't be having any of these ions in the solution.
01:44
So looking at the change, we are looking at a decrease by 3 .2 by 10 to the power negative 4.
01:50
We are looking at an increase by 3 .2 by 10 to the power negative 4.
01:54
We're looking at an increase of 3 .2 by 10 to the power negative 4 because what we are looking for at equilibrium is this concentration of 3 .2 by 10 to the power negative 4...